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How To Calculate Mean Kinetic Temperature

Mean Kinetic Temperature Formula:

\[ MKT = \frac{-2.303}{Days} \times \log_{10} \left( e^{\frac{\Delta H}{R} \times \frac{1}{T_1 + \cdots + \frac{1}{T_n}}{n}} \right) \]

days
J/mol

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1. What Is Mean Kinetic Temperature?

Mean Kinetic Temperature (MKT) is a calculated temperature that represents the cumulative thermal stress experienced by a product over a period of time. It is widely used in pharmaceutical and food industries for stability testing and shelf-life determination.

2. How Does The Calculator Work?

The calculator uses the MKT formula:

\[ MKT = \frac{-2.303}{Days} \times \log_{10} \left( e^{\frac{\Delta H}{R} \times \frac{1}{T_1 + \cdots + \frac{1}{T_n}}{n}} \right) \]

Where:

Explanation: The formula calculates a single temperature that would produce the same thermal degradation as the varying temperatures over time, based on the Arrhenius equation.

3. Importance Of MKT Calculation

Details: MKT is crucial for determining product stability, establishing expiration dates, and ensuring regulatory compliance in industries where temperature-sensitive products are stored and transported.

4. Using The Calculator

Tips: Enter the number of days, enthalpy value in J/mol, and temperature readings in Kelvin separated by commas. Ensure all temperatures are in Kelvin and enthalpy is a positive value.

5. Frequently Asked Questions (FAQ)

Q1: Why Use MKT Instead Of Average Temperature?
A: MKT accounts for the exponential relationship between temperature and degradation rate, providing a more accurate representation of thermal stress than simple arithmetic mean.

Q2: What Is A Typical ΔH Value For Pharmaceutical Products?
A: Typical ΔH values range from 50,000 to 150,000 J/mol, with 83,144 J/mol (20 kcal/mol) being commonly used as a default for many pharmaceuticals.

Q3: How Do I Convert Celsius To Kelvin?
A: Add 273.15 to the Celsius temperature: K = °C + 273.15

Q4: What Is The Significance Of The 2.303 Factor?
A: The factor 2.303 is used for conversion between natural logarithm (ln) and base-10 logarithm (log10): 2.303 = 1/ln(10)

Q5: How Many Temperature Readings Are Needed?
A: More readings provide better accuracy. For stability studies, readings are typically taken at regular intervals (e.g., hourly, daily) throughout the study period.

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