Electric Motor Sizing Formula:
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Electric motor sizing involves determining the appropriate horsepower rating for an electric motor based on the required torque and rotational speed. Proper sizing ensures efficient operation and prevents motor failure.
The calculator uses the horsepower formula:
Where:
Explanation: The constant 5252 comes from the relationship between horsepower, torque, and RPM, where 1 horsepower equals 550 foot-pounds per second.
Details: Correct motor sizing is crucial for energy efficiency, operational reliability, and preventing premature motor failure. Oversized motors waste energy, while undersized motors can overheat and fail.
Tips: Enter load torque in ft-lb and speed in RPM. Ensure values are positive and realistic for your application. Consider adding a safety factor of 10-20% to the calculated horsepower.
Q1: Why is the constant 5252 used?
A: 5252 is derived from the conversion between foot-pounds per minute and horsepower (1 HP = 33,000 ft-lb/min ÷ 2π ≈ 5252).
Q2: What is a typical safety factor for motor sizing?
A: Most applications use a 10-20% safety factor above calculated requirements to account for startup loads and variations.
Q3: How do I measure load torque?
A: Load torque can be measured using torque sensors or calculated based on the mechanical system's requirements and load characteristics.
Q4: What if my torque is in Newton-meters?
A: Convert Newton-meters to foot-pounds by multiplying by 0.737562 before using this calculator.
Q5: Can this calculator be used for all motor types?
A: This formula works for most electric motors, but special applications may require additional considerations for acceleration, duty cycle, and environmental factors.